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13044001232022 = 2310597205152421
BaseRepresentation
bin1011110111010000101100…
…0011110101010010010110
31201011222211212120201020120
42331310023003311102112
53202203103303411042
643424155331412410
72514253340036565
oct275641303652226
951158755521216
1013044001232022
114179a25703662
121568021754106
137380759a1097
14331493b87bdc
15179487588dec
hexbdd0b0f5496

13044001232022 has 16 divisors (see below), whose sum is σ = 26090464420272. Its totient is φ = 4347590084640.

The previous prime is 13044001232011. The next prime is 13044001232089. The reversal of 13044001232022 is 22023210044031.

It is a happy number.

It is a junction number, because it is equal to n+sod(n) for n = 13044001231983 and 13044001232001.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 102512629 + ... + 102639792.

It is an arithmetic number, because the mean of its divisors is an integer number (1630654026267).

Almost surely, 213044001232022 is an apocalyptic number.

13044001232022 is an abundant number, since it is smaller than the sum of its proper divisors (13046463188250).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13044001232022 is a wasteful number, since it uses less digits than its factorization.

13044001232022 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 205163023.

The product of its (nonzero) digits is 2304, while the sum is 24.

Adding to 13044001232022 its reverse (22023210044031), we get a palindrome (35067211276053).

The spelling of 13044001232022 in words is "thirteen trillion, forty-four billion, one million, two hundred thirty-two thousand, twenty-two".

Divisors: 1 2 3 6 10597 21194 31791 63582 205152421 410304842 615457263 1230914526 2174000205337 4348000410674 6522000616011 13044001232022