Base | Representation |
---|---|
bin | 11101101010001001101111… |
… | …000101001010000011110111 |
3 | 122002211221111022000202010102 |
4 | 131222021233011022003313 |
5 | 114044112130210334143 |
6 | 1141231152414144315 |
7 | 36321660206336534 |
oct | 3552115705120367 |
9 | 562757438022112 |
10 | 130440020402423 |
11 | 38620335a53276 |
12 | 12768196ab209b |
13 | 57a259726a404 |
14 | 242d48b51dd8b |
15 | 101309e6590b8 |
hex | 76a26f14a0f7 |
130440020402423 has 2 divisors, whose sum is σ = 130440020402424. Its totient is φ = 130440020402422.
The previous prime is 130440020402389. The next prime is 130440020402431. The reversal of 130440020402423 is 324204020044031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130440020402423 - 210 = 130440020401399 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130440020402453) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65220010201211 + 65220010201212.
It is an arithmetic number, because the mean of its divisors is an integer number (65220010201212).
Almost surely, 2130440020402423 is an apocalyptic number.
130440020402423 is a deficient number, since it is larger than the sum of its proper divisors (1).
130440020402423 is an equidigital number, since it uses as much as digits as its factorization.
130440020402423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18432, while the sum is 29.
Adding to 130440020402423 its reverse (324204020044031), we get a palindrome (454644040446454).
The spelling of 130440020402423 in words is "one hundred thirty trillion, four hundred forty billion, twenty million, four hundred two thousand, four hundred twenty-three".
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