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130440020402389 is a prime number
BaseRepresentation
bin11101101010001001101111…
…000101001010000011010101
3122002211221111022000202002011
4131222021233011022003111
5114044112130210334024
61141231152414144221
736321660206336455
oct3552115705120325
9562757438022064
10130440020402389
1138620335a53245
1212768196ab2071
1357a259726a3a9
14242d48b51dd65
15101309e659094
hex76a26f14a0d5

130440020402389 has 2 divisors, whose sum is σ = 130440020402390. Its totient is φ = 130440020402388.

The previous prime is 130440020402317. The next prime is 130440020402423. The reversal of 130440020402389 is 983204020044031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 83048044824900 + 47391975577489 = 9113070^2 + 6884183^2 .

It is an emirp because it is prime and its reverse (983204020044031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130440020402389 - 237 = 130302581448917 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130440027402389) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65220010201194 + 65220010201195.

It is an arithmetic number, because the mean of its divisors is an integer number (65220010201195).

Almost surely, 2130440020402389 is an apocalyptic number.

It is an amenable number.

130440020402389 is a deficient number, since it is larger than the sum of its proper divisors (1).

130440020402389 is an equidigital number, since it uses as much as digits as its factorization.

130440020402389 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 165888, while the sum is 40.

The spelling of 130440020402389 in words is "one hundred thirty trillion, four hundred forty billion, twenty million, four hundred two thousand, three hundred eighty-nine".