Base | Representation |
---|---|
bin | 11101101010001001101111… |
… | …001100111001101001010100 |
3 | 122002211221111102211212122112 |
4 | 131222021233030321221110 |
5 | 114044112131220313330 |
6 | 1141231152525450152 |
7 | 36321660232522625 |
oct | 3552115714715124 |
9 | 562757442755575 |
10 | 130440022432340 |
11 | 3862033710a395 |
12 | 12768197710958 |
13 | 57a25977cb34a |
14 | 242d48b8cba4c |
15 | 101309e90a795 |
hex | 76a26f339a54 |
130440022432340 has 576 divisors, whose sum is σ = 308739465216000. Its totient is φ = 46098219847680.
The previous prime is 130440022432337. The next prime is 130440022432361. The reversal of 130440022432340 is 43234220044031.
It is a junction number, because it is equal to n+sod(n) for n = 130440022432297 and 130440022432306.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 655477499561 + ... + 655477499759.
It is an arithmetic number, because the mean of its divisors is an integer number (536006016000).
Almost surely, 2130440022432340 is an apocalyptic number.
130440022432340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 130440022432340, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (154369732608000).
130440022432340 is an abundant number, since it is smaller than the sum of its proper divisors (178299442783660).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130440022432340 is a wasteful number, since it uses less digits than its factorization.
130440022432340 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 596 (or 523 counting only the distinct ones).
The product of its (nonzero) digits is 55296, while the sum is 32.
Adding to 130440022432340 its reverse (43234220044031), we get a palindrome (173674242476371).
The spelling of 130440022432340 in words is "one hundred thirty trillion, four hundred forty billion, twenty-two million, four hundred thirty-two thousand, three hundred forty".
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