1304400234145 has 4 divisors (see below), whose sum is σ = 1565280280980. Its totient is φ = 1043520187312.

The previous prime is 1304400234139. The next prime is 1304400234149. The reversal of 1304400234145 is 5414320044031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 719034465681 + 585365768464 = 847959^2 + 765092^2 .

It is a cyclic number.

It is not a de Polignac number, because 1304400234145 - 2⁷ = 1304400234017 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1304400234149) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 130440023410 + ... + 130440023419.

It is an arithmetic number, because the mean of its divisors is an integer number (391320070245).

Almost surely, 2^{1304400234145} is an apocalyptic number.

It is an amenable number.

1304400234145 is a deficient number, since it is larger than the sum of its proper divisors (260880046835).

1304400234145 is an equidigital number, since it uses as much as digits as its factorization.

1304400234145 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 260880046834.

The product of its (nonzero) digits is 23040, while the sum is 31.

Adding to 1304400234145 its reverse (5414320044031), we get a palindrome (6718720278176).

The spelling of 1304400234145 in words is "one trillion, three hundred four billion, four hundred million, two hundred thirty-four thousand, one hundred forty-five".