13044011111 has 4 divisors (see below), whose sum is σ = 13238697912. Its totient is φ = 12849324312.

The previous prime is 13044011083. The next prime is 13044011153. The reversal of 13044011111 is 11111044031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13044011111 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13044011111.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13044011611) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 97343300 + ... + 97343433.

It is an arithmetic number, because the mean of its divisors is an integer number (3309674478).

Almost surely, 2^13044011111 is an apocalyptic number.

13044011111 is a deficient number, since it is larger than the sum of its proper divisors (194686801).

13044011111 is an equidigital number, since it uses as much as digits as its factorization.

13044011111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 194686800.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 13044011111 its reverse (11111044031), we get a palindrome (24155055142).

The spelling of 13044011111 in words is "thirteen billion, forty-four million, eleven thousand, one hundred eleven".