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1304401443134 = 2652200721567
BaseRepresentation
bin10010111110110100011…
…000100111100100111110
311121200212222102221010112
4102332310120213210332
5132332403232140014
62435122253510022
7163145166220166
oct22766430474476
94550788387115
101304401443134
114632146775a9
121909754a2312
1396009c4426a
14471c1d5b5a6
1523de554673e
hex12fb462793e

1304401443134 has 4 divisors (see below), whose sum is σ = 1956602164704. Its totient is φ = 652200721566.

The previous prime is 1304401443133. The next prime is 1304401443157. The reversal of 1304401443134 is 4313441044031.

It is a semiprime because it is the product of two primes.

It is a self number, because there is not a number n which added to its sum of digits gives 1304401443134.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1304401443133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 326100360782 + ... + 326100360785.

It is an arithmetic number, because the mean of its divisors is an integer number (489150541176).

Almost surely, 21304401443134 is an apocalyptic number.

1304401443134 is a deficient number, since it is larger than the sum of its proper divisors (652200721570).

1304401443134 is an equidigital number, since it uses as much as digits as its factorization.

1304401443134 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 652200721569.

The product of its (nonzero) digits is 27648, while the sum is 32.

Adding to 1304401443134 its reverse (4313441044031), we get a palindrome (5617842487165).

The spelling of 1304401443134 in words is "one trillion, three hundred four billion, four hundred one million, four hundred forty-three thousand, one hundred thirty-four".

Divisors: 1 2 652200721567 1304401443134