Base | Representation |
---|---|
bin | 10010111110110100100… |
… | …011001000101101101111 |
3 | 11121200220011122000020220 |
4 | 102332310203020231233 |
5 | 132332404433402203 |
6 | 2435122432542423 |
7 | 163145231522451 |
oct | 22766443105557 |
9 | 4550804560226 |
10 | 1304404200303 |
11 | 463216190056 |
12 | 1909763b1a13 |
13 | 9600a69b219 |
14 | 471c24782d1 |
15 | 23de58dd653 |
hex | 12fb48c8b6f |
1304404200303 has 4 divisors (see below), whose sum is σ = 1739205600408. Its totient is φ = 869602800200.
The previous prime is 1304404200299. The next prime is 1304404200343. The reversal of 1304404200303 is 3030024044031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1304404200303 - 22 = 1304404200299 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1304404200343) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 217400700048 + ... + 217400700053.
It is an arithmetic number, because the mean of its divisors is an integer number (434801400102).
Almost surely, 21304404200303 is an apocalyptic number.
1304404200303 is a deficient number, since it is larger than the sum of its proper divisors (434801400105).
1304404200303 is an equidigital number, since it uses as much as digits as its factorization.
1304404200303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 434801400104.
The product of its (nonzero) digits is 3456, while the sum is 24.
Adding to 1304404200303 its reverse (3030024044031), we get a palindrome (4334428244334).
The spelling of 1304404200303 in words is "one trillion, three hundred four billion, four hundred four million, two hundred thousand, three hundred three".
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