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130440421333 is a prime number
BaseRepresentation
bin111100101111011011…
…0101101111111010101
3110110200121122222010001
41321132312231333111
54114120221440313
6135531250531301
712265302200365
oct1713666557725
9413617588101
10130440421333
1150357243202
1221344296b31
13c3ba1c9681
146455b929a5
1535d685dadd
hex1e5edadfd5

130440421333 has 2 divisors, whose sum is σ = 130440421334. Its totient is φ = 130440421332.

The previous prime is 130440421273. The next prime is 130440421367. The reversal of 130440421333 is 333124044031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 99034201809 + 31406219524 = 314697^2 + 177218^2 .

It is an emirp because it is prime and its reverse (333124044031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130440421333 - 29 = 130440420821 is a prime.

It is a super-2 number, since 2×1304404213332 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130440421373) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65220210666 + 65220210667.

It is an arithmetic number, because the mean of its divisors is an integer number (65220210667).

Almost surely, 2130440421333 is an apocalyptic number.

It is an amenable number.

130440421333 is a deficient number, since it is larger than the sum of its proper divisors (1).

130440421333 is an equidigital number, since it uses as much as digits as its factorization.

130440421333 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10368, while the sum is 28.

Adding to 130440421333 its reverse (333124044031), we get a palindrome (463564465364).

The spelling of 130440421333 in words is "one hundred thirty billion, four hundred forty million, four hundred twenty-one thousand, three hundred thirty-three".