Base | Representation |
---|---|
bin | 111100101111011011… |
… | …0101101111111111101 |
3 | 110110200121122222011112 |
4 | 1321132312231333331 |
5 | 4114120221440443 |
6 | 135531250531405 |
7 | 12265302200453 |
oct | 1713666557775 |
9 | 413617588145 |
10 | 130440421373 |
11 | 50357243239 |
12 | 21344296b65 |
13 | c3ba1c96b2 |
14 | 6455b929d3 |
15 | 35d685db18 |
hex | 1e5edadffd |
130440421373 has 2 divisors, whose sum is σ = 130440421374. Its totient is φ = 130440421372.
The previous prime is 130440421369. The next prime is 130440421481. The reversal of 130440421373 is 373124044031.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 125501564644 + 4938856729 = 354262^2 + 70277^2 .
It is an emirp because it is prime and its reverse (373124044031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 130440421373 - 22 = 130440421369 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130440421333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65220210686 + 65220210687.
It is an arithmetic number, because the mean of its divisors is an integer number (65220210687).
Almost surely, 2130440421373 is an apocalyptic number.
It is an amenable number.
130440421373 is a deficient number, since it is larger than the sum of its proper divisors (1).
130440421373 is an equidigital number, since it uses as much as digits as its factorization.
130440421373 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24192, while the sum is 32.
The spelling of 130440421373 in words is "one hundred thirty billion, four hundred forty million, four hundred twenty-one thousand, three hundred seventy-three".
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