Base | Representation |
---|---|
bin | 11101101010001010101010… |
… | …101010010111001100111001 |
3 | 122002212001001221222010202012 |
4 | 131222022222222113030321 |
5 | 114044121202110330241 |
6 | 1141231435523215305 |
7 | 36322024035021305 |
oct | 3552125252271471 |
9 | 562761057863665 |
10 | 130441020011321 |
11 | 386207a922a228 |
12 | 12768415817535 |
13 | 57a26c639b576 |
14 | 242d5441a8d05 |
15 | 101310c2ae6eb |
hex | 76a2aaa97339 |
130441020011321 has 2 divisors, whose sum is σ = 130441020011322. Its totient is φ = 130441020011320.
The previous prime is 130441020011317. The next prime is 130441020011347. The reversal of 130441020011321 is 123110020144031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 130014976612921 + 426043398400 = 11402411^2 + 652720^2 .
It is a cyclic number.
It is not a de Polignac number, because 130441020011321 - 22 = 130441020011317 is a prime.
It is not a weakly prime, because it can be changed into another prime (130441020011021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65220510005660 + 65220510005661.
It is an arithmetic number, because the mean of its divisors is an integer number (65220510005661).
Almost surely, 2130441020011321 is an apocalyptic number.
It is an amenable number.
130441020011321 is a deficient number, since it is larger than the sum of its proper divisors (1).
130441020011321 is an equidigital number, since it uses as much as digits as its factorization.
130441020011321 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 130441020011321 its reverse (123110020144031), we get a palindrome (253551040155352).
The spelling of 130441020011321 in words is "one hundred thirty trillion, four hundred forty-one billion, twenty million, eleven thousand, three hundred twenty-one".
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