130441020011317 has 2 divisors, whose sum is σ = 130441020011318. Its totient is φ = 130441020011316.

The previous prime is 130441020011303. The next prime is 130441020011321. The reversal of 130441020011317 is 713110020144031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 72633449420676 + 57807570590641 = 8522526^2 + 7603129^2 .

It is an emirp because it is prime and its reverse (713110020144031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130441020011317 - 2¹⁹ = 130441019487029 is a prime.

It is a super-4 number, since 4×130441020011317⁴ (a number of 58 digits) contains 4444 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130441020011347) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65220510005658 + 65220510005659.

It is an arithmetic number, because the mean of its divisors is an integer number (65220510005659).

Almost surely, 2^{130441020011317} is an apocalyptic number.

It is an amenable number.

130441020011317 is a deficient number, since it is larger than the sum of its proper divisors (1).

130441020011317 is an equidigital number, since it uses as much as digits as its factorization.

130441020011317 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2016, while the sum is 28.

Adding to 130441020011317 its reverse (713110020144031), we get a palindrome (843551040155348).

The spelling of 130441020011317 in words is "one hundred thirty trillion, four hundred forty-one billion, twenty million, eleven thousand, three hundred seventeen".