130441020012047 has 2 divisors, whose sum is σ = 130441020012048. Its totient is φ = 130441020012046.

The previous prime is 130441020012011. The next prime is 130441020012049. The reversal of 130441020012047 is 740210020144031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 130441020012047 - 2²⁴ = 130441003234831 is a prime.

Together with 130441020012049, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130441020012049) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65220510006023 + 65220510006024.

It is an arithmetic number, because the mean of its divisors is an integer number (65220510006024).

Almost surely, 2^{130441020012047} is an apocalyptic number.

130441020012047 is a deficient number, since it is larger than the sum of its proper divisors (1).

130441020012047 is an equidigital number, since it uses as much as digits as its factorization.

130441020012047 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5376, while the sum is 29.

Adding to 130441020012047 its reverse (740210020144031), we get a palindrome (870651040156078).

The spelling of 130441020012047 in words is "one hundred thirty trillion, four hundred forty-one billion, twenty million, twelve thousand, forty-seven".