130441022403133 has 4 divisors (see below), whose sum is σ = 140474947203388. Its totient is φ = 120407097602880.

The previous prime is 130441022403091. The next prime is 130441022403137. The reversal of 130441022403133 is 331304220144031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 73755753605689 + 56685268797444 = 8588117^2 + 7528962^2 .

It is a cyclic number.

It is not a de Polignac number, because 130441022403133 - 2²⁵ = 130440988848701 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130441022403095 and 130441022403104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130441022403137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5016962400108 + ... + 5016962400133.

It is an arithmetic number, because the mean of its divisors is an integer number (35118736800847).

Almost surely, 2^{130441022403133} is an apocalyptic number.

130441022403133 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

130441022403133 is a deficient number, since it is larger than the sum of its proper divisors (10033924800255).

130441022403133 is a wasteful number, since it uses less digits than its factorization.

130441022403133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10033924800254.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 130441022403133 its reverse (331304220144031), we get a palindrome (461745242547164).

The spelling of 130441022403133 in words is "one hundred thirty trillion, four hundred forty-one billion, twenty-two million, four hundred three thousand, one hundred thirty-three".