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1304410303444 = 222931362739239
BaseRepresentation
bin10010111110110100111…
…010011010101111010100
311121200220121010002012011
4102332310322122233110
5132332413014202234
62435123211434004
7163145334432043
oct22766472325724
94550817102164
101304410303444
11463219679476
12190978455904
139600ba27151
14471c31c655a
1523de61e6b64
hex12fb4e9abd4

1304410303444 has 24 divisors (see below), whose sum is σ = 2437607692800. Its totient is φ = 609401919840.

The previous prime is 1304410303439. The next prime is 1304410303457. The reversal of 1304410303444 is 4443030144031.

It is a happy number.

It is a super-2 number, since 2×13044103034442 (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (31).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 181366024 + ... + 181373215.

It is an arithmetic number, because the mean of its divisors is an integer number (101566987200).

Almost surely, 21304410303444 is an apocalyptic number.

It is an amenable number.

1304410303444 is a deficient number, since it is larger than the sum of its proper divisors (1133197389356).

1304410303444 is a wasteful number, since it uses less digits than its factorization.

1304410303444 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 362739303 (or 362739301 counting only the distinct ones).

The product of its (nonzero) digits is 27648, while the sum is 31.

Adding to 1304410303444 its reverse (4443030144031), we get a palindrome (5747440447475).

The spelling of 1304410303444 in words is "one trillion, three hundred four billion, four hundred ten million, three hundred three thousand, four hundred forty-four".

Divisors: 1 2 4 29 31 58 62 116 124 899 1798 3596 362739239 725478478 1450956956 10519437931 11244916409 21038875862 22489832818 42077751724 44979665636 326102575861 652205151722 1304410303444