130441030962131 has 2 divisors, whose sum is σ = 130441030962132. Its totient is φ = 130441030962130.

The previous prime is 130441030962103. The next prime is 130441030962133. The reversal of 130441030962131 is 131269030144031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 130441030962131 - 2²² = 130441026767827 is a prime.

It is a super-2 number, since 2×130441030962131² (a number of 29 digits) contains 22 as substring.

Together with 130441030962133, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (130441030962133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65220515481065 + 65220515481066.

It is an arithmetic number, because the mean of its divisors is an integer number (65220515481066).

Almost surely, 2^{130441030962131} is an apocalyptic number.

130441030962131 is a deficient number, since it is larger than the sum of its proper divisors (1).

130441030962131 is an equidigital number, since it uses as much as digits as its factorization.

130441030962131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 46656, while the sum is 38.

The spelling of 130441030962131 in words is "one hundred thirty trillion, four hundred forty-one billion, thirty million, nine hundred sixty-two thousand, one hundred thirty-one".