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130441030962133 is a prime number
BaseRepresentation
bin11101101010001010101011…
…010100001000101111010101
3122002212001002201120111102211
4131222022223110020233111
5114044121212411242013
61141231440554033421
736322024230061003
oct3552125324105725
9562761081514384
10130441030962133
1138620804429791
1212768419418871
1357a26c8733b38
14242d545819a73
15101310d22423d
hex76a2ab508bd5

130441030962133 has 2 divisors, whose sum is σ = 130441030962134. Its totient is φ = 130441030962132.

The previous prime is 130441030962131. The next prime is 130441030962157. The reversal of 130441030962133 is 331269030144031.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 120215918347204 + 10225112614929 = 10964302^2 + 3197673^2 .

It is a cyclic number.

It is not a de Polignac number, because 130441030962133 - 21 = 130441030962131 is a prime.

Together with 130441030962131, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130441030962131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65220515481066 + 65220515481067.

It is an arithmetic number, because the mean of its divisors is an integer number (65220515481067).

Almost surely, 2130441030962133 is an apocalyptic number.

It is an amenable number.

130441030962133 is a deficient number, since it is larger than the sum of its proper divisors (1).

130441030962133 is an equidigital number, since it uses as much as digits as its factorization.

130441030962133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 139968, while the sum is 40.

The spelling of 130441030962133 in words is "one hundred thirty trillion, four hundred forty-one billion, thirty million, nine hundred sixty-two thousand, one hundred thirty-three".