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130441031210029 is a prime number
BaseRepresentation
bin11101101010001010101011…
…010101000101010000101101
3122002212001002202001002111011
4131222022223111011100231
5114044121212442210104
61141231441003225221
736322024232142511
oct3552125325052055
9562761082032434
10130441031210029
1138620804588a61
1212768419518211
1357a26c87bc917
14242d545882141
15101310d272904
hex76a2ab54542d

130441031210029 has 2 divisors, whose sum is σ = 130441031210030. Its totient is φ = 130441031210028.

The previous prime is 130441031209981. The next prime is 130441031210047. The reversal of 130441031210029 is 920012130144031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 121892132387529 + 8548898822500 = 11040477^2 + 2923850^2 .

It is a cyclic number.

It is not a de Polignac number, because 130441031210029 - 217 = 130441031078957 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130441031510029) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65220515605014 + 65220515605015.

It is an arithmetic number, because the mean of its divisors is an integer number (65220515605015).

Almost surely, 2130441031210029 is an apocalyptic number.

It is an amenable number.

130441031210029 is a deficient number, since it is larger than the sum of its proper divisors (1).

130441031210029 is an equidigital number, since it uses as much as digits as its factorization.

130441031210029 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5184, while the sum is 31.

The spelling of 130441031210029 in words is "one hundred thirty trillion, four hundred forty-one billion, thirty-one million, two hundred ten thousand, twenty-nine".