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130441031224277 is a prime number
BaseRepresentation
bin11101101010001010101011…
…010101001000101111010101
3122002212001002202001211000212
4131222022223111020233111
5114044121212443134102
61141231441003415205
736322024232232164
oct3552125325105725
9562761082054025
10130441031224277
1138620804598734
1212768419524505
1357a26c87c6257
14242d5458873db
15101310d276c52
hex76a2ab548bd5

130441031224277 has 2 divisors, whose sum is σ = 130441031224278. Its totient is φ = 130441031224276.

The previous prime is 130441031224237. The next prime is 130441031224337. The reversal of 130441031224277 is 772422130144031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 87535465769521 + 42905565454756 = 9356039^2 + 6550234^2 .

It is an emirp because it is prime and its reverse (772422130144031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130441031224277 - 218 = 130441030962133 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130441031224237) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65220515612138 + 65220515612139.

It is an arithmetic number, because the mean of its divisors is an integer number (65220515612139).

Almost surely, 2130441031224277 is an apocalyptic number.

It is an amenable number.

130441031224277 is a deficient number, since it is larger than the sum of its proper divisors (1).

130441031224277 is an equidigital number, since it uses as much as digits as its factorization.

130441031224277 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 225792, while the sum is 41.

The spelling of 130441031224277 in words is "one hundred thirty trillion, four hundred forty-one billion, thirty-one million, two hundred twenty-four thousand, two hundred seventy-seven".