Base | Representation |
---|---|
bin | 11101101010001010101011… |
… | …010101001000101111010111 |
3 | 122002212001002202001211000221 |
4 | 131222022223111020233113 |
5 | 114044121212443134104 |
6 | 1141231441003415211 |
7 | 36322024232232166 |
oct | 3552125325105727 |
9 | 562761082054027 |
10 | 130441031224279 |
11 | 38620804598736 |
12 | 12768419524507 |
13 | 57a26c87c6259 |
14 | 242d5458873dd |
15 | 101310d276c54 |
hex | 76a2ab548bd7 |
130441031224279 has 8 divisors (see below), whose sum is σ = 133654186334592. Its totient is φ = 127236041693880.
The previous prime is 130441031224277. The next prime is 130441031224337. The reversal of 130441031224279 is 972422130144031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 130441031224279 - 21 = 130441031224277 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (43).
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130441031224277) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2041362637 + ... + 2041426534.
It is an arithmetic number, because the mean of its divisors is an integer number (16706773291824).
Almost surely, 2130441031224279 is an apocalyptic number.
130441031224279 is a deficient number, since it is larger than the sum of its proper divisors (3213155110313).
130441031224279 is an equidigital number, since it uses as much as digits as its factorization.
130441031224279 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4082789957.
The product of its (nonzero) digits is 290304, while the sum is 43.
The spelling of 130441031224279 in words is "one hundred thirty trillion, four hundred forty-one billion, thirty-one million, two hundred twenty-four thousand, two hundred seventy-nine".
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