Base | Representation |
---|---|
bin | 11101101010001010101011… |
… | …011000000111101001011111 |
3 | 122002212001002210112112200102 |
4 | 131222022223120013221133 |
5 | 114044121213143144424 |
6 | 1141231441032251315 |
7 | 36322024242000023 |
oct | 3552125330075137 |
9 | 562761083475612 |
10 | 130441032006239 |
11 | 38620804a82189 |
12 | 12768419840b3b |
13 | 57a26c8a0b156 |
14 | 242d545a0c383 |
15 | 101310d37d7ae |
hex | 76a2ab607a5f |
130441032006239 has 2 divisors, whose sum is σ = 130441032006240. Its totient is φ = 130441032006238.
The previous prime is 130441032006227. The next prime is 130441032006251. The reversal of 130441032006239 is 932600230144031.
It is a balanced prime because it is at equal distance from previous prime (130441032006227) and next prime (130441032006251).
It is an emirp because it is prime and its reverse (932600230144031) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130441032006239 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130441032005239) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65220516003119 + 65220516003120.
It is an arithmetic number, because the mean of its divisors is an integer number (65220516003120).
Almost surely, 2130441032006239 is an apocalyptic number.
130441032006239 is a deficient number, since it is larger than the sum of its proper divisors (1).
130441032006239 is an equidigital number, since it uses as much as digits as its factorization.
130441032006239 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 93312, while the sum is 38.
The spelling of 130441032006239 in words is "one hundred thirty trillion, four hundred forty-one billion, thirty-two million, six thousand, two hundred thirty-nine".
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