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130441032020021 is a prime number
BaseRepresentation
bin11101101010001010101011…
…011000001011000000110101
3122002212001002210120020120212
4131222022223120023000311
5114044121213144120041
61141231441032435205
736322024242055142
oct3552125330130065
9562761083506525
10130441032020021
1138620804a91578
1212768419848b05
1357a26c8a144c8
14242d545a133c9
15101310d3828eb
hex76a2ab60b035

130441032020021 has 2 divisors, whose sum is σ = 130441032020022. Its totient is φ = 130441032020020.

The previous prime is 130441032019943. The next prime is 130441032020077. The reversal of 130441032020021 is 120020230144031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 129657187397521 + 783844622500 = 11386711^2 + 885350^2 .

It is a cyclic number.

It is not a de Polignac number, because 130441032020021 - 226 = 130440964911157 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130441032020821) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65220516010010 + 65220516010011.

It is an arithmetic number, because the mean of its divisors is an integer number (65220516010011).

Almost surely, 2130441032020021 is an apocalyptic number.

It is an amenable number.

130441032020021 is a deficient number, since it is larger than the sum of its proper divisors (1).

130441032020021 is an equidigital number, since it uses as much as digits as its factorization.

130441032020021 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 130441032020021 its reverse (120020230144031), we get a palindrome (250461262164052).

The spelling of 130441032020021 in words is "one hundred thirty trillion, four hundred forty-one billion, thirty-two million, twenty thousand, twenty-one".