130441032102340 has 12 divisors (see below), whose sum is σ = 273926167414956. Its totient is φ = 52176412840928.

The previous prime is 130441032102323. The next prime is 130441032102377. The reversal of 130441032102340 is 43201230144031.

It is a happy number.

130441032102340 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 2 ways, for example, as 79537002395904 + 50904029706436 = 8918352^2 + 7134706^2 .

It is a junction number, because it is equal to n+sod(n) for n = 130441032102299 and 130441032102308.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3261025802539 + ... + 3261025802578.

It is an arithmetic number, because the mean of its divisors is an integer number (22827180617913).

Almost surely, 2^{130441032102340} is an apocalyptic number.

130441032102340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

130441032102340 is an abundant number, since it is smaller than the sum of its proper divisors (143485135312616).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130441032102340 is a wasteful number, since it uses less digits than its factorization.

130441032102340 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6522051605126 (or 6522051605124 counting only the distinct ones).

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 130441032102340 its reverse (43201230144031), we get a palindrome (173642262246371).

The spelling of 130441032102340 in words is "one hundred thirty trillion, four hundred forty-one billion, thirty-two million, one hundred two thousand, three hundred forty".