Base | Representation |
---|---|
bin | 111100101111011100… |
… | …1101111010101110101 |
3 | 110110200200011012111012 |
4 | 1321132321233111311 |
5 | 4114120422311201 |
6 | 135531315522005 |
7 | 12265312006340 |
oct | 1713671572565 |
9 | 413620135435 |
10 | 130441213301 |
11 | 50357734223 |
12 | 213445b9305 |
13 | c3ba415ca9 |
14 | 6455d1b457 |
15 | 35d69685bb |
hex | 1e5ee6f575 |
130441213301 has 4 divisors (see below), whose sum is σ = 149075672352. Its totient is φ = 111806754252.
The previous prime is 130441213297. The next prime is 130441213319. The reversal of 130441213301 is 103312144031.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 130441213301 - 22 = 130441213297 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130441213351) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9317229515 + ... + 9317229528.
It is an arithmetic number, because the mean of its divisors is an integer number (37268918088).
Almost surely, 2130441213301 is an apocalyptic number.
It is an amenable number.
130441213301 is a deficient number, since it is larger than the sum of its proper divisors (18634459051).
130441213301 is an equidigital number, since it uses as much as digits as its factorization.
130441213301 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 18634459050.
The product of its (nonzero) digits is 864, while the sum is 23.
Adding to 130441213301 its reverse (103312144031), we get a palindrome (233753357332).
The spelling of 130441213301 in words is "one hundred thirty billion, four hundred forty-one million, two hundred thirteen thousand, three hundred one".
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