Base | Representation |
---|---|
bin | 111100101111011100… |
… | …1110011111010110010 |
3 | 110110200200012011012121 |
4 | 1321132321303322302 |
5 | 4114120423411200 |
6 | 135531320144454 |
7 | 12265312115113 |
oct | 1713671637262 |
9 | 413620164177 |
10 | 130441232050 |
11 | 50357747318 |
12 | 2134460812a |
13 | c3ba42169c |
14 | 6455d2420a |
15 | 35d696de1a |
hex | 1e5ee73eb2 |
130441232050 has 48 divisors (see below), whose sum is σ = 257008182120. Its totient is φ = 49085173760.
The previous prime is 130441232039. The next prime is 130441232063. The reversal of 130441232050 is 50232144031.
It can be written as a sum of positive squares in 12 ways, for example, as 1537973089 + 128903258961 = 39217^2 + 359031^2 .
It is a Harshad number since it is a multiple of its sum of digits (25).
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1919046 + ... + 1985854.
Almost surely, 2130441232050 is an apocalyptic number.
130441232050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
130441232050 is a deficient number, since it is larger than the sum of its proper divisors (126566950070).
130441232050 is a wasteful number, since it uses less digits than its factorization.
130441232050 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 69135 (or 69130 counting only the distinct ones).
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 130441232050 its reverse (50232144031), we get a palindrome (180673376081).
The spelling of 130441232050 in words is "one hundred thirty billion, four hundred forty-one million, two hundred thirty-two thousand, fifty".
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