130441244321301 has 4 divisors (see below), whose sum is σ = 173921659095072. Its totient is φ = 86960829547532.

The previous prime is 130441244321257. The next prime is 130441244321303. The reversal of 130441244321301 is 103123442144031.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 130441244321301 - 2¹⁵ = 130441244288533 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130441244321303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21740207386881 + ... + 21740207386886.

It is an arithmetic number, because the mean of its divisors is an integer number (43480414773768).

Almost surely, 2^{130441244321301} is an apocalyptic number.

It is an amenable number.

130441244321301 is a deficient number, since it is larger than the sum of its proper divisors (43480414773771).

130441244321301 is an equidigital number, since it uses as much as digits as its factorization.

130441244321301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43480414773770.

The product of its (nonzero) digits is 27648, while the sum is 33.

Adding to 130441244321301 its reverse (103123442144031), we get a palindrome (233564686465332).

The spelling of 130441244321301 in words is "one hundred thirty trillion, four hundred forty-one billion, two hundred forty-four million, three hundred twenty-one thousand, three hundred one".