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13044241023001 is a prime number
BaseRepresentation
bin1011110111010001100101…
…0110100100000000011001
31201012000110120210100121221
42331310121112210000121
53202204101200214001
643424235215132041
72514262311161626
oct275643126440031
951160416710557
1013044241023001
11417a038aa4121
121568089b14021
137380b357aa36
143314b796734d
1517949d6531a1
hexbdd195a4019

13044241023001 has 2 divisors, whose sum is σ = 13044241023002. Its totient is φ = 13044241023000.

The previous prime is 13044241022977. The next prime is 13044241023091. The reversal of 13044241023001 is 10032014244031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13043827917376 + 413105625 = 3611624^2 + 20325^2 .

It is a cyclic number.

It is not a de Polignac number, because 13044241023001 - 215 = 13044240990233 is a prime.

It is a super-2 number, since 2×130442410230012 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13044241023091) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6522120511500 + 6522120511501.

It is an arithmetic number, because the mean of its divisors is an integer number (6522120511501).

Almost surely, 213044241023001 is an apocalyptic number.

It is an amenable number.

13044241023001 is a deficient number, since it is larger than the sum of its proper divisors (1).

13044241023001 is an equidigital number, since it uses as much as digits as its factorization.

13044241023001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 13044241023001 its reverse (10032014244031), we get a palindrome (23076255267032).

The spelling of 13044241023001 in words is "thirteen trillion, forty-four billion, two hundred forty-one million, twenty-three thousand, one".