13044241023000 has 256 divisors, whose sum is σ = 44406380528640. Its totient is φ = 3161632896000.

The previous prime is 13044241022977. The next prime is 13044241023001. The reversal of 13044241023000 is 32014244031.

It is a super-2 number, since 2×13044241023000² (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (24).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13044241023001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 185523852 + ... + 185594148.

It is an arithmetic number, because the mean of its divisors is an integer number (173462423940).

Almost surely, 2^{13044241023000} is an apocalyptic number.

13044241023000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13044241023000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (22203190264320).

13044241023000 is an abundant number, since it is smaller than the sum of its proper divisors (31362139505640).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13044241023000 is a wasteful number, since it uses less digits than its factorization.

13044241023000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 75955 (or 75941 counting only the distinct ones).

The product of its (nonzero) digits is 2304, while the sum is 24.

Adding to 13044241023000 its reverse (32014244031), we get a palindrome (13076255267031).

The spelling of 13044241023000 in words is "thirteen trillion, forty-four billion, two hundred forty-one million, twenty-three thousand".