13044251341 has 4 divisors (see below), whose sum is σ = 14230092384. Its totient is φ = 11858410300.

The previous prime is 13044251333. The next prime is 13044251377. The reversal of 13044251341 is 14315244031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14315244031 = 11 ⋅1301385821.

It is not a de Polignac number, because 13044251341 - 2³ = 13044251333 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13044251741) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 592920505 + ... + 592920526.

It is an arithmetic number, because the mean of its divisors is an integer number (3557523096).

Almost surely, 2^13044251341 is an apocalyptic number.

13044251341 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

13044251341 is a deficient number, since it is larger than the sum of its proper divisors (1185841043).

13044251341 is a wasteful number, since it uses less digits than its factorization.

13044251341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1185841042.

The product of its (nonzero) digits is 5760, while the sum is 28.

Adding to 13044251341 its reverse (14315244031), we get a palindrome (27359495372).

The spelling of 13044251341 in words is "thirteen billion, forty-four million, two hundred fifty-one thousand, three hundred forty-one".