130443010031 has 2 divisors, whose sum is σ = 130443010032. Its totient is φ = 130443010030.

The previous prime is 130443010021. The next prime is 130443010079. The reversal of 130443010031 is 130010344031.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 130443010031 - 2¹⁴ = 130442993647 is a prime.

It is a super-2 number, since 2×130443010031² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 130443009985 and 130443010012.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130443010021) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65221505015 + 65221505016.

It is an arithmetic number, because the mean of its divisors is an integer number (65221505016).

Almost surely, 2^130443010031 is an apocalyptic number.

130443010031 is a deficient number, since it is larger than the sum of its proper divisors (1).

130443010031 is an equidigital number, since it uses as much as digits as its factorization.

130443010031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 130443010031 its reverse (130010344031), we get a palindrome (260453354062).

The spelling of 130443010031 in words is "one hundred thirty billion, four hundred forty-three million, ten thousand, thirty-one".