Base | Representation |
---|---|
bin | 111100101111100000… |
… | …0100110000000011111 |
3 | 110110200210112111012112 |
4 | 1321133000212000133 |
5 | 4114121402310304 |
6 | 135531422224235 |
7 | 12265333201634 |
oct | 1713700460037 |
9 | 413623474175 |
10 | 130443010079 |
11 | 50358751168 |
12 | 2134512507b |
13 | c3ba8c4a85 |
14 | 645626818b |
15 | 35d6bc0b6e |
hex | 1e5f02601f |
130443010079 has 2 divisors, whose sum is σ = 130443010080. Its totient is φ = 130443010078.
The previous prime is 130443010031. The next prime is 130443010081. The reversal of 130443010079 is 970010344031.
It is a strong prime.
It is an emirp because it is prime and its reverse (970010344031) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130443010079 is a prime.
Together with 130443010081, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130443010979) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65221505039 + 65221505040.
It is an arithmetic number, because the mean of its divisors is an integer number (65221505040).
Almost surely, 2130443010079 is an apocalyptic number.
130443010079 is a deficient number, since it is larger than the sum of its proper divisors (1).
130443010079 is an equidigital number, since it uses as much as digits as its factorization.
130443010079 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9072, while the sum is 32.
The spelling of 130443010079 in words is "one hundred thirty billion, four hundred forty-three million, ten thousand, seventy-nine".
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