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13044311141 is a prime number
BaseRepresentation
bin11000010011000000…
…00110010001100101
31020200002011122220212
430021200012101211
5203203320424031
65554212505205
7641151546431
oct141140062145
936602148825
1013044311141
1155941a0034
12264061b205
1312cb617904
148ba5c19c1
155152a612b
hex309806465

13044311141 has 2 divisors, whose sum is σ = 13044311142. Its totient is φ = 13044311140.

The previous prime is 13044311131. The next prime is 13044311153. The reversal of 13044311141 is 14111344031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9160404100 + 3883907041 = 95710^2 + 62321^2 .

It is a cyclic number.

It is not a de Polignac number, because 13044311141 - 210 = 13044310117 is a prime.

It is a super-3 number, since 3×130443111413 (a number of 31 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13044311101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6522155570 + 6522155571.

It is an arithmetic number, because the mean of its divisors is an integer number (6522155571).

Almost surely, 213044311141 is an apocalyptic number.

It is an amenable number.

13044311141 is a deficient number, since it is larger than the sum of its proper divisors (1).

13044311141 is an equidigital number, since it uses as much as digits as its factorization.

13044311141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 13044311141 its reverse (14111344031), we get a palindrome (27155655172).

The spelling of 13044311141 in words is "thirteen billion, forty-four million, three hundred eleven thousand, one hundred forty-one".