130444543045 has 4 divisors (see below), whose sum is σ = 156533451660. Its totient is φ = 104355634432.

The previous prime is 130444543037. The next prime is 130444543049. The reversal of 130444543045 is 540345444031.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 540345444031 = 43 ⋅12566173117.

It can be written as a sum of positive squares in 2 ways, for example, as 65179111204 + 65265431841 = 255302^2 + 255471^2 .

It is a cyclic number.

It is not a de Polignac number, because 130444543045 - 2³ = 130444543037 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 130444542995 and 130444543013.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130444543049) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13044454300 + ... + 13044454309.

It is an arithmetic number, because the mean of its divisors is an integer number (39133362915).

Almost surely, 2^130444543045 is an apocalyptic number.

It is an amenable number.

130444543045 is a deficient number, since it is larger than the sum of its proper divisors (26088908615).

130444543045 is an equidigital number, since it uses as much as digits as its factorization.

130444543045 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26088908614.

The product of its (nonzero) digits is 230400, while the sum is 37.

Adding to 130444543045 its reverse (540345444031), we get a palindrome (670789987076).

The spelling of 130444543045 in words is "one hundred thirty billion, four hundred forty-four million, five hundred forty-three thousand, forty-five".