Base | Representation |
---|---|
bin | 10010111110111010010… |
… | …000110010100000001111 |
3 | 11121201010211222212211222 |
4 | 102332322100302200033 |
5 | 132333104003212111 |
6 | 2435140135233555 |
7 | 163150504335416 |
oct | 22767220624017 |
9 | 4551124885758 |
10 | 1304500054031 |
11 | 4632652aa409 |
12 | 1909a25188bb |
13 | 960244bc6c5 |
14 | 471d10aa47d |
15 | 23dee0247db |
hex | 12fba43280f |
1304500054031 has 2 divisors, whose sum is σ = 1304500054032. Its totient is φ = 1304500054030.
The previous prime is 1304500054027. The next prime is 1304500054057.
1304500054031 is nontrivially palindromic in base 10.
It is an a-pointer prime, because the next prime (1304500054057) can be obtained adding 1304500054031 to its sum of digits (26).
It is a weak prime.
It is a palprime.
It is a cyclic number.
It is not a de Polignac number, because 1304500054031 - 22 = 1304500054027 is a prime.
It is a super-2 number, since 2×13045000540312 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1304500554031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652250027015 + 652250027016.
It is an arithmetic number, because the mean of its divisors is an integer number (652250027016).
Almost surely, 21304500054031 is an apocalyptic number.
1304500054031 is a deficient number, since it is larger than the sum of its proper divisors (1).
1304500054031 is an equidigital number, since it uses as much as digits as its factorization.
1304500054031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3600, while the sum is 26.
It can be divided in two parts, 13045000 and 54031, that added together give a palindrome (13099031).
The spelling of 1304500054031 in words is "one trillion, three hundred four billion, five hundred million, fifty-four thousand, thirty-one".
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