Base | Representation |
---|---|
bin | 111100110000001000… |
… | …0110000110000111101 |
3 | 110110202021002012011102 |
4 | 1321200100300300331 |
5 | 4114142242310121 |
6 | 135533452502445 |
7 | 12266006630564 |
oct | 1714020606075 |
9 | 413667065142 |
10 | 130464025661 |
11 | 503695a5512 |
12 | 2135017aa25 |
13 | c3c2072528 |
14 | 6458d78bdb |
15 | 35d897290b |
hex | 1e60430c3d |
130464025661 has 2 divisors, whose sum is σ = 130464025662. Its totient is φ = 130464025660.
The previous prime is 130464025649. The next prime is 130464025663. The reversal of 130464025661 is 166520464031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 108368689636 + 22095336025 = 329194^2 + 148645^2 .
It is a cyclic number.
It is not a de Polignac number, because 130464025661 - 210 = 130464024637 is a prime.
Together with 130464025663, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130464025663) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65232012830 + 65232012831.
It is an arithmetic number, because the mean of its divisors is an integer number (65232012831).
Almost surely, 2130464025661 is an apocalyptic number.
It is an amenable number.
130464025661 is a deficient number, since it is larger than the sum of its proper divisors (1).
130464025661 is an equidigital number, since it uses as much as digits as its factorization.
130464025661 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 103680, while the sum is 38.
Adding to 130464025661 its reverse (166520464031), we get a palindrome (296984489692).
The spelling of 130464025661 in words is "one hundred thirty billion, four hundred sixty-four million, twenty-five thousand, six hundred sixty-one".
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