130473217179648 has 1800 divisors, whose sum is σ = 476431508931840. Its totient is φ = 35431765770240.

The previous prime is 130473217179637. The next prime is 130473217179653. The reversal of 130473217179648 is 846971712374031.

130473217179648 is a `hidden beast` number, since 1 + 3 + 0 + 473 + 2 + 1 + 71 + 7 + 96 + 4 + 8 = 666.

130473217179648 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (63).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 119 ways as a sum of consecutive naturals, for example, 118936387036 + ... + 118936388132.

Almost surely, 2^{130473217179648} is an apocalyptic number.

130473217179648 is a gapful number since it is divisible by the number (18) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 130473217179648, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (238215754465920).

130473217179648 is an abundant number, since it is smaller than the sum of its proper divisors (345958291752192).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130473217179648 is an equidigital number, since it uses as much as digits as its factorization.

130473217179648 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1241 (or 1199 counting only the distinct ones).

The product of its (nonzero) digits is 42674688, while the sum is 63.

The spelling of 130473217179648 in words is "one hundred thirty trillion, four hundred seventy-three billion, two hundred seventeen million, one hundred seventy-nine thousand, six hundred forty-eight".