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1304798893 is a prime number
BaseRepresentation
bin100110111000101…
…1010011010101101
310100221012122120221
41031301122122231
510133012031033
6333250211341
744222415256
oct11561323255
93327178527
101304798893
1160a5857a2
12304b83b51
1317a428368
14c540db2d
157983c12d
hex4dc5a6ad

1304798893 has 2 divisors, whose sum is σ = 1304798894. Its totient is φ = 1304798892.

The previous prime is 1304798857. The next prime is 1304798917. The reversal of 1304798893 is 3988974031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1304798884 + 9 = 36122^2 + 3^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1304798893 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1304798893.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1304798843) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652399446 + 652399447.

It is an arithmetic number, because the mean of its divisors is an integer number (652399447).

Almost surely, 21304798893 is an apocalyptic number.

It is an amenable number.

1304798893 is a deficient number, since it is larger than the sum of its proper divisors (1).

1304798893 is an equidigital number, since it uses as much as digits as its factorization.

1304798893 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1306368, while the sum is 52.

The square root of 1304798893 is about 36122.0001245778. Note that the first 3 decimals coincide. The cubic root of 1304798893 is about 1092.7341769614.

The spelling of 1304798893 in words is "one billion, three hundred four million, seven hundred ninety-eight thousand, eight hundred ninety-three".