1305025552541 has 4 divisors (see below), whose sum is σ = 1381791761532. Its totient is φ = 1228259343552.

The previous prime is 1305025552513. The next prime is 1305025552561. The reversal of 1305025552541 is 1452555205031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1006117326916 + 298908225625 = 1003054^2 + 546725^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1305025552541 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1305025552495 and 1305025552504.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1305025552561) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 38383104470 + ... + 38383104503.

It is an arithmetic number, because the mean of its divisors is an integer number (345447940383).

Almost surely, 2^{1305025552541} is an apocalyptic number.

It is an amenable number.

1305025552541 is a deficient number, since it is larger than the sum of its proper divisors (76766208991).

1305025552541 is an equidigital number, since it uses as much as digits as its factorization.

1305025552541 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 76766208990.

The product of its (nonzero) digits is 150000, while the sum is 38.

The spelling of 1305025552541 in words is "one trillion, three hundred five billion, twenty-five million, five hundred fifty-two thousand, five hundred forty-one".