Base | Representation |
---|---|
bin | 1011110111101000101011… |
… | …0110000010000011001111 |
3 | 1201012121110121101022220121 |
4 | 2331322022312002003033 |
5 | 3202304300124041411 |
6 | 43431142302125411 |
7 | 2514602033155222 |
oct | 275721266020317 |
9 | 51177417338817 |
10 | 13050440065231 |
11 | 418172a213318 |
12 | 1569319b80867 |
13 | 738860956b6a |
14 | 331904d895b9 |
15 | 1797129a6571 |
hex | bde8ad820cf |
13050440065231 has 2 divisors, whose sum is σ = 13050440065232. Its totient is φ = 13050440065230.
The previous prime is 13050440065211. The next prime is 13050440065253. The reversal of 13050440065231 is 13256004405031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13050440065231 - 229 = 13049903194319 is a prime.
It is a super-2 number, since 2×130504400652312 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13050440065211) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6525220032615 + 6525220032616.
It is an arithmetic number, because the mean of its divisors is an integer number (6525220032616).
Almost surely, 213050440065231 is an apocalyptic number.
13050440065231 is a deficient number, since it is larger than the sum of its proper divisors (1).
13050440065231 is an equidigital number, since it uses as much as digits as its factorization.
13050440065231 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 43200, while the sum is 34.
The spelling of 13050440065231 in words is "thirteen trillion, fifty billion, four hundred forty million, sixty-five thousand, two hundred thirty-one".
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