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130515432535 = 559874359961
BaseRepresentation
bin111100110001101010…
…0110111010001010111
3110110212211210221010201
41321203110313101113
54114243422320120
6135542530401331
712300202605055
oct1714324672127
9413784727121
10130515432535
1150395617234
1221365430247
13c3cc9010b7
146461b1b1d5
1535dd22940a
hex1e63537457

130515432535 has 8 divisors (see below), whose sum is σ = 156644714736. Its totient is φ = 104394882240.

The previous prime is 130515432503. The next prime is 130515432547. The reversal of 130515432535 is 535234515031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 130515432535 - 25 = 130515432503 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130515432494 and 130515432503.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2150046 + ... + 2209915.

It is an arithmetic number, because the mean of its divisors is an integer number (19580589342).

Almost surely, 2130515432535 is an apocalyptic number.

130515432535 is a deficient number, since it is larger than the sum of its proper divisors (26129282201).

130515432535 is an equidigital number, since it uses as much as digits as its factorization.

130515432535 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4365953.

The product of its (nonzero) digits is 135000, while the sum is 37.

Adding to 130515432535 its reverse (535234515031), we get a palindrome (665749947566).

The spelling of 130515432535 in words is "one hundred thirty billion, five hundred fifteen million, four hundred thirty-two thousand, five hundred thirty-five".

Divisors: 1 5 5987 29935 4359961 21799805 26103086507 130515432535