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130521311013 = 343507103671
BaseRepresentation
bin111100110001110101…
…1010010011100100101
3110110220020212120220010
41321203223102130211
54114301423423023
6135543300400433
712300303560352
oct1714353223445
9413806776803
10130521311013
1150398971885
12213673a6119
13c400bab9a2
14646280b629
1535dd9db093
hex1e63ad2725

130521311013 has 4 divisors (see below), whose sum is σ = 174028414688. Its totient is φ = 87014207340.

The previous prime is 130521310981. The next prime is 130521311021. The reversal of 130521311013 is 310113125031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 130521311013 - 25 = 130521310981 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130521310013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21753551833 + ... + 21753551838.

It is an arithmetic number, because the mean of its divisors is an integer number (43507103672).

Almost surely, 2130521311013 is an apocalyptic number.

It is an amenable number.

130521311013 is a deficient number, since it is larger than the sum of its proper divisors (43507103675).

130521311013 is an equidigital number, since it uses as much as digits as its factorization.

130521311013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 43507103674.

The product of its (nonzero) digits is 270, while the sum is 21.

Adding to 130521311013 its reverse (310113125031), we get a palindrome (440634436044).

The spelling of 130521311013 in words is "one hundred thirty billion, five hundred twenty-one million, three hundred eleven thousand, thirteen".

Divisors: 1 3 43507103671 130521311013