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1305254365141 is a prime number
BaseRepresentation
bin10010111111100111001…
…110010000011111010101
311121210002102100212011111
4102333213032100133111
5132341130104141031
62435343042535021
7163205264021236
oct22774716203725
94553072325144
101305254365141
11463612074521
12190b73067471
139611486653c
144726334108d
1523e453741b1
hex12fe73907d5

1305254365141 has 2 divisors, whose sum is σ = 1305254365142. Its totient is φ = 1305254365140.

The previous prime is 1305254365139. The next prime is 1305254365169. The reversal of 1305254365141 is 1415634525031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1295792912241 + 9461452900 = 1138329^2 + 97270^2 .

It is a cyclic number.

It is not a de Polignac number, because 1305254365141 - 21 = 1305254365139 is a prime.

Together with 1305254365139, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 1305254365094 and 1305254365103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1305254365171) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652627182570 + 652627182571.

It is an arithmetic number, because the mean of its divisors is an integer number (652627182571).

Almost surely, 21305254365141 is an apocalyptic number.

It is an amenable number.

1305254365141 is a deficient number, since it is larger than the sum of its proper divisors (1).

1305254365141 is an equidigital number, since it uses as much as digits as its factorization.

1305254365141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216000, while the sum is 40.

The spelling of 1305254365141 in words is "one trillion, three hundred five billion, two hundred fifty-four million, three hundred sixty-five thousand, one hundred forty-one".