Base | Representation |
---|---|
bin | 1011110111110010010101… |
… | …0010101000010000001000 |
3 | 1201012212011012011022021222 |
4 | 2331330211102220100020 |
5 | 3202330102000044000 |
6 | 43432251344221212 |
7 | 2515023165664424 |
oct | 275744522502010 |
9 | 51185135138258 |
10 | 13053031253000 |
11 | 418283993a012 |
12 | 156992190a808 |
13 | 738b84732a6b |
14 | 331aad175b84 |
15 | 1798151e5a85 |
hex | bdf254a8408 |
13053031253000 has 32 divisors (see below), whose sum is σ = 30544093134360. Its totient is φ = 5221212500800.
The previous prime is 13053031252981. The next prime is 13053031253029. The reversal of 13053031253000 is 35213035031.
It can be written as a sum of positive squares in 4 ways, for example, as 2719339517764 + 10333691735236 = 1649042^2 + 3214606^2 .
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6526514627 + ... + 6526516626.
Almost surely, 213053031253000 is an apocalyptic number.
13053031253000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13053031253000 is an abundant number, since it is smaller than the sum of its proper divisors (17491061881360).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13053031253000 is a wasteful number, since it uses less digits than its factorization.
13053031253000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13053031274 (or 13053031260 counting only the distinct ones).
The product of its (nonzero) digits is 4050, while the sum is 26.
Adding to 13053031253000 its reverse (35213035031), we get a palindrome (13088244288031).
The spelling of 13053031253000 in words is "thirteen trillion, fifty-three billion, thirty-one million, two hundred fifty-three thousand".
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