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130534040134005 = 358702269342267
BaseRepresentation
bin11101101011100001010011…
…000101111110000101110101
3122010011221011200201222100020
4131223201103011332011311
5114102132203233242010
61141342302111235353
736331526126020254
oct3553412305760565
9563157150658306
10130534040134005
11386571a2705182
1212782455b18b59
1357ab3cbacc291
142433c4a22a79b
151015753857470
hex76b85317e175

130534040134005 has 8 divisors (see below), whose sum is σ = 208854464214432. Its totient is φ = 69618154738128.

The previous prime is 130534040133953. The next prime is 130534040134067. The reversal of 130534040134005 is 500431040435031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 130534040134005 - 213 = 130534040125813 is a prime.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4351134671119 + ... + 4351134671148.

It is an arithmetic number, because the mean of its divisors is an integer number (26106808026804).

Almost surely, 2130534040134005 is an apocalyptic number.

130534040134005 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

130534040134005 is a deficient number, since it is larger than the sum of its proper divisors (78320424080427).

130534040134005 is an equidigital number, since it uses as much as digits as its factorization.

130534040134005 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8702269342275.

The product of its (nonzero) digits is 43200, while the sum is 33.

Adding to 130534040134005 its reverse (500431040435031), we get a palindrome (630965080569036).

The spelling of 130534040134005 in words is "one hundred thirty trillion, five hundred thirty-four billion, forty million, one hundred thirty-four thousand, five".

Divisors: 1 3 5 15 8702269342267 26106808026801 43511346711335 130534040134005