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130540214111 = 152338569567
BaseRepresentation
bin111100110010011001…
…1011001011101011111
3110110221120102222001212
41321210303121131133
54114321243322421
6135545213455035
712300623340416
oct1714463313537
9413846388055
10130540214111
11503a8602a7a
12213717a147b
13c404a99a58
14646512c47d
1535e04c1e5b
hex1e64cd975f

130540214111 has 4 divisors (see below), whose sum is σ = 130548798912. Its totient is φ = 130531629312.

The previous prime is 130540214099. The next prime is 130540214179. The reversal of 130540214111 is 111412045031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130540214111 - 218 = 130539951967 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130540214711) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4269551 + ... + 4300016.

It is an arithmetic number, because the mean of its divisors is an integer number (32637199728).

Almost surely, 2130540214111 is an apocalyptic number.

130540214111 is a deficient number, since it is larger than the sum of its proper divisors (8584801).

130540214111 is an equidigital number, since it uses as much as digits as its factorization.

130540214111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8584800.

The product of its (nonzero) digits is 480, while the sum is 23.

Adding to 130540214111 its reverse (111412045031), we get a palindrome (241952259142).

The spelling of 130540214111 in words is "one hundred thirty billion, five hundred forty million, two hundred fourteen thousand, one hundred eleven".

Divisors: 1 15233 8569567 130540214111