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1305422124119 is a prime number
BaseRepresentation
bin10010111111110001001…
…110001101010001010111
311121210112010000220012222
4102333301032031101113
5132342001030432434
62435411434332555
7163212401654411
oct22776116152127
94553463026188
101305422124119
11463698836303
12190bbb28a15b
13961405427c9
144727b72d9b1
1523e54e6072e
hex12ff138d457

1305422124119 has 2 divisors, whose sum is σ = 1305422124120. Its totient is φ = 1305422124118.

The previous prime is 1305422124049. The next prime is 1305422124133. The reversal of 1305422124119 is 9114212245031.

It is a strong prime.

It is an emirp because it is prime and its reverse (9114212245031) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1305422124119 is a prime.

It is a super-2 number, since 2×13054221241192 (a number of 25 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1305422124619) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652711062059 + 652711062060.

It is an arithmetic number, because the mean of its divisors is an integer number (652711062060).

Almost surely, 21305422124119 is an apocalyptic number.

1305422124119 is a deficient number, since it is larger than the sum of its proper divisors (1).

1305422124119 is an equidigital number, since it uses as much as digits as its factorization.

1305422124119 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 17280, while the sum is 35.

The spelling of 1305422124119 in words is "one trillion, three hundred five billion, four hundred twenty-two million, one hundred twenty-four thousand, one hundred nineteen".