Base | Representation |
---|---|
bin | 10010111111110001010… |
… | …101100100001110100001 |
3 | 11121210112020122220100200 |
4 | 102333301111210032201 |
5 | 132342002024200103 |
6 | 2435411543535413 |
7 | 163212424240413 |
oct | 22776125441641 |
9 | 4553466586320 |
10 | 1305424053153 |
11 | 463699933650 |
12 | 190bbba5a569 |
13 | 96140a6984c |
14 | 4727bab29b3 |
15 | 23e551e20a3 |
hex | 12ff15643a1 |
1305424053153 has 24 divisors (see below), whose sum is σ = 2065638706560. Its totient is φ = 787855760160.
The previous prime is 1305424053151. The next prime is 1305424053169. The reversal of 1305424053153 is 3513504245031.
1305424053153 is a `hidden beast` number, since 1 + 3 + 0 + 54 + 24 + 0 + 531 + 53 = 666.
It is not a de Polignac number, because 1305424053153 - 21 = 1305424053151 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1305424053151) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 27562326 + ... + 27609647.
It is an arithmetic number, because the mean of its divisors is an integer number (86068279440).
Almost surely, 21305424053153 is an apocalyptic number.
It is an amenable number.
1305424053153 is a deficient number, since it is larger than the sum of its proper divisors (760214653407).
1305424053153 is a wasteful number, since it uses less digits than its factorization.
1305424053153 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 55172229 (or 55172226 counting only the distinct ones).
The product of its (nonzero) digits is 108000, while the sum is 36.
Adding to 1305424053153 its reverse (3513504245031), we get a palindrome (4818928298184).
The spelling of 1305424053153 in words is "one trillion, three hundred five billion, four hundred twenty-four million, fifty-three thousand, one hundred fifty-three".
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