Base | Representation |
---|---|
bin | 1011110111111010000111… |
… | …0010100111010100000001 |
3 | 1201020001112202112021201121 |
4 | 2331332201302213110001 |
5 | 3202343341210400140 |
6 | 43433234521432241 |
7 | 2515126021104412 |
oct | 275764162472401 |
9 | 51201482467647 |
10 | 13055120012545 |
11 | 418371099aa76 |
12 | 156a20533b681 |
13 | 7391283b6560 |
14 | 331c2a737809 |
15 | 1798d878c64a |
hex | bdfa1ca7501 |
13055120012545 has 32 divisors (see below), whose sum is σ = 16978645595520. Its totient is φ = 9579408399360.
The previous prime is 13055120012491. The next prime is 13055120012569. The reversal of 13055120012545 is 54521002155031.
It is a de Polignac number, because none of the positive numbers 2k-13055120012545 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13055120012545.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 14586217 + ... + 15455353.
It is an arithmetic number, because the mean of its divisors is an integer number (530582674860).
Almost surely, 213055120012545 is an apocalyptic number.
It is an amenable number.
13055120012545 is a deficient number, since it is larger than the sum of its proper divisors (3923525582975).
13055120012545 is a wasteful number, since it uses less digits than its factorization.
13055120012545 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 870625.
The product of its (nonzero) digits is 30000, while the sum is 34.
Adding to 13055120012545 its reverse (54521002155031), we get a palindrome (67576122167576).
The spelling of 13055120012545 in words is "thirteen trillion, fifty-five billion, one hundred twenty million, twelve thousand, five hundred forty-five".
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