Base | Representation |
---|---|
bin | 111100110010110010… |
… | …0100011111011100010 |
3 | 110110222110200201222221 |
4 | 1321211210203323202 |
5 | 4114333043231200 |
6 | 135550354021254 |
7 | 12301141025530 |
oct | 1714544437342 |
9 | 413873621887 |
10 | 130553102050 |
11 | 50404905968 |
12 | 21375b7782a |
13 | c40765cc57 |
14 | 6466b25150 |
15 | 35e16ba91a |
hex | 1e65923ee2 |
130553102050 has 48 divisors (see below), whose sum is σ = 279515234880. Its totient is φ = 44439024960.
The previous prime is 130553102047. The next prime is 130553102051. The reversal of 130553102050 is 50201355031.
It is a super-2 number, since 2×1305531020502 (a number of 23 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (25).
It is not an unprimeable number, because it can be changed into a prime (130553102051) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1293109 + ... + 1390408.
It is an arithmetic number, because the mean of its divisors is an integer number (5823234060).
Almost surely, 2130553102050 is an apocalyptic number.
130553102050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
130553102050 is an abundant number, since it is smaller than the sum of its proper divisors (148962132830).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130553102050 is a wasteful number, since it uses less digits than its factorization.
130553102050 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2683675 (or 2683670 counting only the distinct ones).
The product of its (nonzero) digits is 2250, while the sum is 25.
Adding to 130553102050 its reverse (50201355031), we get a palindrome (180754457081).
The spelling of 130553102050 in words is "one hundred thirty billion, five hundred fifty-three million, one hundred two thousand, fifty".
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