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130553214013 = 1104711817979
BaseRepresentation
bin111100110010110010…
…0111111010000111101
3110110222110220102120201
41321211210333100331
54114333110322023
6135550400243501
712301142003125
oct1714544772075
9413873812521
10130553214013
1150404981aa2
1221376010591
13c40769bbc1
146466b53c85
1535e16ddbad
hex1e6593f43d

130553214013 has 4 divisors (see below), whose sum is σ = 130565043040. Its totient is φ = 130541384988.

The previous prime is 130553213981. The next prime is 130553214061. The reversal of 130553214013 is 310412355031.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 130553214013 - 25 = 130553213981 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130553217013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5897943 + ... + 5920036.

It is an arithmetic number, because the mean of its divisors is an integer number (32641260760).

Almost surely, 2130553214013 is an apocalyptic number.

It is an amenable number.

130553214013 is a deficient number, since it is larger than the sum of its proper divisors (11829027).

130553214013 is a wasteful number, since it uses less digits than its factorization.

130553214013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11829026.

The product of its (nonzero) digits is 5400, while the sum is 28.

Adding to 130553214013 its reverse (310412355031), we get a palindrome (440965569044).

The spelling of 130553214013 in words is "one hundred thirty billion, five hundred fifty-three million, two hundred fourteen thousand, thirteen".

Divisors: 1 11047 11817979 130553214013